(4y^4/x^6)/(16y^2/3x)

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Solution for (4y^4/x^6)/(16y^2/3x) equation: 


D( x )

x^6 = 0

x*((16*y^2)/3) = 0

x^6 = 0

x^6 = 0

1*x^6 = 0 // : 1

x^6 = 0

x = 0

x*((16*y^2)/3) = 0

x*((16*y^2)/3) = 0

16/3*x*y^2 = 0 // : 16/3*y^2

x = 0

x in (-oo:0) U (0:+oo)

((4*y^4)/(x^6))/(x*((16*y^2)/3)) = 0

3/4*x^-7*y^2 = 0 // : 3/4*y^2

x^-7 = 0

x naleu017Cy do O

x belongs to the empty set

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